35^2=(g-11)(g-8)

Solution for 35^2=(g-11)(g-8) equation:

35^2=(g-11)(g-8)

We move all terms to the left:

35^2-((g-11)(g-8))=0

We add all the numbers together, and all the variables

-((g-11)(g-8))+1225=0

We multiply parentheses ..

-((+g^2-8g-11g+88))+1225=0


We calculate terms in parentheses: -((+g^2-8g-11g+88)), so:

(+g^2-8g-11g+88)

We get rid of parentheses

g^2-8g-11g+88

We add all the numbers together, and all the variables

g^2-19g+88

Back to the equation:

-(g^2-19g+88)


We get rid of parentheses

-g^2+19g-88+1225=0

We add all the numbers together, and all the variables

-1g^2+19g+1137=0

a = -1; b = 19; c = +1137;
Δ = b2-4ac
Δ = 192-4·(-1)·1137
Δ = 4909
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-\sqrt{4909}}{2*-1}=\frac{-19-\sqrt{4909}}{-2}
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+\sqrt{4909}}{2*-1}=\frac{-19+\sqrt{4909}}{-2}
$